Elevation of Missouri Farmland
Inputting and graphing the data
| > | x:=[0,.1,.2,.3,.4,.5,.6,.7,.8,.9,1,1.1,1.2,1.3,1.4,1.5]: y:=[0,.1,.2,.3,.4,.5,.6,.7,.8,.9,1,1.1,1.2,1.3,1.4,1.5]: r[16]:=[800.3,799.1,798.3,797.8,797.5,797.4,797.4,797.5,797.6,797.7,797.6,797.3,796.8,796.0,794.8,793.2]: r[15]:=[800.8,799.6,798.8,798.3,798.0,797.9,797.9,798.0,798.1,798.1,798.1,797.8,797.3,796.5,795.3,793.7]: r[14]:=[801.2,800.0,799.2,798.7,798.4,798.3,798.3,798.4,798.5,798.6,798.5,798.2,797.7,796.9,795.7,794.1]: r[13]:=[801.6,800.4,799.6,799.1,798.8,798.7,798.7,798.8,798.9,798.9,798.9,798.6,798.1,797.3,796.1,794.5]: r[12]:=[801.9,800.7,799.9,799.4,799.1,799.0,799.0,799.1,799.2,799.3,799.2,798.9,798.4,797.6,796.4,794.8]: r[11]:=[802.2,801.0,800.2,799.7,799.4,799.3,799.3,799.4,799.5,799.5,799.5,799.2,798.7,797.9,796.7,795.1]: r[10]:=[802.4,801.2,800.4,799.9,799.6,799.5,799.5,799.6,799.7,799.8,799.7,799.4,798.9,798.1,796.9,795.3]: r[9]:=[802.6,801.4,800.6,800.1,799.8,799.7,799.7,799.8,799.9,799.9,799.9,799.6,799.1,798.3,797.1,795.5]: r[8]:=[802.7,801.5,800.7,800.2,799.9,799.8,799.8,799.9,800.0,800.1,800.0,799.7,799.2,798.4,797.2,795.6]: r[7]:=[802.8,801.6,800.8,800.3,800.0,799.9,799.9,800.0,800.1,800.1,800.1,799.8,799.3,798.5,797.3,795.7]: r[6]:=[802.8,801.6,800.8,800.3,800.0,799.9,799.9,800.0,800.1,800.2,800.1,799.8,799.3,798.5,797.3,795.7]: r[5]:=[802.8,801.6,800.8,800.3,800.0,799.9,799.9,800.0,800.1,800.1,800.1,799.8,799.3,798.5,797.3,795.7]: r[4]:=[802.7,801.5,800.7,800.2,799.9,799.8,799.8,799.9,800.0,800.1,800.0,799.7,799.2,798.4,797.2,795.6]: r[3]:=[802.6,801.4,800.6,800.1,799.8,799.7,799.7,799.8,799.9,799.9,799.9,799.6,799.1,798.3,797.1,795.5]: r[2]:=[802.4,801.2,800.4,799.9,799.6,799.5,799.5,799.6,799.7,799.8,799.7,799.4,798.9,798.1,796.9,795.3]: r[1]:=[802.2,801.0,800.2,799.7,799.4,799.3,799.3,799.4,799.5,799.5,799.5,799.2,798.7,797.9,796.7,795.1]: |
Pointplot of data:
formula for elevation - and the graph
The formula below (and its graph) uses "x and y" instead of "e and n":
Using "e and n", and rounding coefficients to three decimal places we have the formula:
.
cross sectional model (from data)
(elevation 0.6 miles north of southern fence)
Highlighting the elevations along the line "n=0.6" (a cross-section)
Using the TI-83 we find that when n=0.6, the elevation E is given as a function of e:
.
Drawing this "cross sectional model" into our picture of the data we get:
cross sectional model (from elevation formula)
We saw earlier that the Elevation of Missouri Farmland Data is pretty well approximated by the formula
.
If we fix n as 0.6, this gives us (upon rounding)
, which is
.
Compare this to our cross sectional model found from the data:
.
Very similar!